【问题】

I have a large number of files with the same, tab-delimited format:

Column A    Column B
Data_A1      Data_B1
Data_A2      Data_B2
Data_A3      Data_B3

These files all have the same number of lines.

I want to compile every file's Column B data into a single tab-delimited file. Right now, my best plan is to write a Perl script along these lines:

#!/usr/bin/perl

my $file = shift @ARGV;
my $ref = shift @ARGV;
open ( FILE, $file ); # FILE WITH FORMAT DESCRIBED ABOVE
while (<FILE>) {
        chomp;
        my @a = split("\t", $_);
        push(@B, $a[1]);
}
close FILE;

my $counter = 0;
open (REF, $ref); # TAB-DELIMITED COMPILATION OF EVERY FILE'S COLUMN B
while (<REF>) {
        chomp;
        print "$_\t$B[$counter]\n";
}
close REF;

Then, write a BASH script that loops through all the files and saving the output of the Perl script as its input for the next iteration of the shell loop:

          <!\-\- /\* Font Definitions */ @font-face {font-family:宋体; panose-1:2 1 6 0 3 1 1 1 1 1; mso-font-alt:SimSun; mso-font-charset:134; mso-generic-font-family:auto; mso-font-pitch:variable; mso-font-signature:3 680460288 22 0 262145 0;} @font-face {font-family:宋体; panose-1:2 1 6 0 3 1 1 1 1 1; mso-font-alt:SimSun; mso-font-charset:134; mso-generic-font-family:auto; mso-font-pitch:variable; mso-font-signature:3 680460288 22 0 262145 0;} @font-face {font-family:Consolas; panose-1:2 11 6 9 2 2 4 3 2 4; mso-font-charset:0; mso-generic-font-family:modern; mso-font-pitch:fixed; mso-font-signature:-536869121 64767 1 0 415 0;} @font-face {font-family:"\\@宋体"; panose-1:2 1 6 0 3 1 1 1 1 1; mso-font-charset:134; mso-generic-font-family:auto; mso-font-pitch:variable; mso-font-signature:3 680460288 22 0 262145 0;} /* Style Definitions */ p.MsoNormal, li.MsoNormal, div.MsoNormal {mso-style-unhide:no; mso-style-qformat:yes; mso-style-parent:""; margin:0cm; margin-bottom:.0001pt; text-align:justify; text-justify:inter-ideograph; mso-pagination:none; font-size:12.0pt; mso-bidi-font-size:10.0pt; font-family:"Times New Roman","serif"; mso-fareast-font-family:宋体; mso-font-kerning:1.0pt;} .MsoChpDefault {mso-style-type:export-only; mso-default-props:yes; font-size:10.0pt; mso-ansi-font-size:10.0pt; mso-bidi-font-size:10.0pt; mso-ascii-font-family:"Times New Roman"; mso-fareast-font-family:宋体; mso-hansi-font-family:"Times New Roman"; mso-font-kerning:0pt;} /* Page Definitions */ @page {mso-page-border-surround-header:no; mso-page-border-surround-footer:no;} @page WordSection1 {size:612.0pt 792.0pt; margin:72.0pt 90.0pt 72.0pt 90.0pt; mso-header-margin:36.0pt; mso-footer-margin:36.0pt; mso-paper-source:0;} div.WordSection1 {page:WordSection1;} -->   

#!/bin/bash

for file in *.txt

 do

perl Script.pl $file Infile \> Temp

mv Temp  Infile

 done

But this feels like a huge amount of work for something so simple. Is there a simple Unix command that can do the same thing?

Expected Output:

File1_Column_B    File2_Column_B    File3_Column_B    ...
Data_B1           Data_B1           Data_B1           ...
Data_B2           Data_B2           Data_B2           ...
Data_B3           Data_B3           Data_B3           ...
...

【回答】

       这个需求涉及一系列的有序算法，尤是其将字段名拼成特定的格式时。可以考虑用SPL解决这个问题，代码如下：

A1：读取文件列表。

A2：取得每个文件的Column_B列数据。

A3：将Column B列数据拼在一起。

A4：将A3结果写入到文件，并修改字段名。