找出每行特定匹配的串
【问题】
From a text file with variable number of columns per row (tab delimited), I would like to extract value with specific condition. The text file looks like:
S1=dhs Sb=skf S3=ghw QS=ghr<b/>
S1=dhf QS=thg S3=eiq<b/>
QS=bhf S3=ruq Gq=qpq GW=tut<b/>
Sb=ruw QS=ooe Gq=qfj GW=uvd<b/>
I would like to have a result like:
QS=ghr<b/>
QS=thg
QS=bhf
QS=ooe
Please excuse my naive question but I am a beginner trying to learn some basic bash scripting technique for text manipulation.
【回答】
Shell可以解决这个问题，只是代码有些难懂，这类处理用SPL的集合运算更方便些，脚本如下：
A |
|
1 |
=file("/file.txt").import() |
2 |
=A1.(~.array()).union() |
3 |
=A2.select(pos(~,"QS")) |
A1：读取文本
A2：将每条记录的字段组合成序列，再将多个序列合并
A3：选出匹配“QS”字符串的成员
